4[2-5(w+3)]+2(w+1)=2

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Solution for 4[2-5(w+3)]+2(w+1)=2 equation:


Simplifying
4[2 + -5(w + 3)] + 2(w + 1) = 2

Reorder the terms:
4[2 + -5(3 + w)] + 2(w + 1) = 2
4[2 + (3 * -5 + w * -5)] + 2(w + 1) = 2
4[2 + (-15 + -5w)] + 2(w + 1) = 2

Combine like terms: 2 + -15 = -13
4[-13 + -5w] + 2(w + 1) = 2
[-13 * 4 + -5w * 4] + 2(w + 1) = 2
[-52 + -20w] + 2(w + 1) = 2

Reorder the terms:
-52 + -20w + 2(1 + w) = 2
-52 + -20w + (1 * 2 + w * 2) = 2
-52 + -20w + (2 + 2w) = 2

Reorder the terms:
-52 + 2 + -20w + 2w = 2

Combine like terms: -52 + 2 = -50
-50 + -20w + 2w = 2

Combine like terms: -20w + 2w = -18w
-50 + -18w = 2

Solving
-50 + -18w = 2

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + -18w = 2 + 50

Combine like terms: -50 + 50 = 0
0 + -18w = 2 + 50
-18w = 2 + 50

Combine like terms: 2 + 50 = 52
-18w = 52

Divide each side by '-18'.
w = -2.888888889

Simplifying
w = -2.888888889

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